The partial derivative with respect to b is going to be flat.

关于 b 的偏导数将是平坦的。

And the partial derivative of this with respect to b, set that equal to 0.

并将其关于 b 的偏导数设为 0。

And the partial derivative of our squared error with respect to b is going to be equal to 0.

并且我们的平方误差关于 b 的偏导数将等于 0。

Just as a reminder, partial derivatives, it's just like taking a regular derivative.

提醒一下，偏导数，就像取正则导数一样。

So its partial derivative with respect to m is 0.

所以它对m的偏导数为0。

So if I were to take the partial derivative of this expression with respect to m.

因此，如果我要对该表达式求关于 m 的偏导数。

So the partial derivatives of either of these with respect to b is 0.

所以它们中的任何一个关于 b 的偏导数都是 0。

So this is the partial derivative with respect to m.

所以这是关于 m 的偏导数。

So at that point, the partial derivative of our squared error with respect to m is going to be equal to 0.

所以在这一点上，我们的平方误差关于 m 的偏导数将等于 0。

But to do that, we're going to find the partial derivative of this with respect to m.

但要做到这一点，我们将找到它关于 m 的偏导数。

The partial derivative of that with respect to b is just going to be the coefficient.

关于 b 的偏导数就是系数。

If you've done any partial derivatives, it won't be difficult.

如果您做过任何偏导数，那将不会很困难。

So the slope in this direction, that's the partial derivative with respect to m, is going to be flat.

所以这个方向的斜率，即关于 m 的偏导数， 将是平坦的。

You're just assuming that everything but the variable that you're doing the partial derivative with respect to, you're assuming everything else is a constant.

您只是假设除了要对其进行偏导的变量之外的所有内容，您都假设其他所有内容都是常数。

So the partial derivative with respect to b is going to be minus 2n, or negative 2n, times the mean of the y's.

所以关于 b 的偏导数将是负 2n，或负 2n，乘以 y 的平均值。

And we're going to find the partial derivative of this with respect to b and set both of them equal to 0.

我们要找到这个关于 b 的偏导数，并将它们都设置为 0。

So all we're going to do, in the next video, is take the partial derivative of this expression with respect to m, set that equal to 0.

因此，在下一个视频中，我们要做的就是对该表达式求关于 m 的偏导数， 并将其设为 0。

Then finally, the partial derivative of this with respect to b is going to be 2nb, Or 2nb to the first you could even say.

最后，关于b的偏导数将是2nb， 或者2nb到你甚至可以说的第一个。

The way that we do that, is we find a point where the partial derivative of the squared error with respect to m is 0, and the partial derivative with respect to b is also equal to 0.

我们这样做的方法是，我们找到一个点， 其中关于 m 的平方误差的偏导数为 0， 并且相对于 b 的偏导数也等于 0。